L&B&H of a cube in the ratio 3:2:1 and L doubled and B & H are halved.then % of decrease in volume of a cube?

• L&B&H of a cube in the ratio 3:2:1 or (3x, 2x,x units) and L doubled (6x)and B (x)& H (0.5x) are halved.
  
  initial volume = 3x*2x*x= 6x^3 units
  Final volume = 6x*x*x/2 = 3x^3 units.
  % decrease in vol = 100*3/6= 50%
• 12 years agoHelpfull: Yes(21) No(2)
• Volume of the cube is=lbh
  
  when l is doubled B&h halve=2*L*(B/2)*(H/2)=LBH/2
  % ecrease in the volume is 50%
• 12 years agoHelpfull: Yes(10) No(1)
• initial h=x,b=2x,l=3x volume=6x^3
  new h=x/2,b=x,l=6x volume=3x^3
  decrease in vol=50%
• 12 years agoHelpfull: Yes(5) No(2)
• 50%
  ratio of vol=(lbh)/(2l*.5B*.5H)=1/.5
  hence %decrement=(1-.5)*100=50%
  
• 12 years agoHelpfull: Yes(4) No(4)