1Q>(222224*444445*222221+666668)/222222^2.WHAT IS THE VALUE
2Q>
(44444445*88888885*44444442+44444438/44444444^2)? WHAT IS THE VALUE

• ans for 2nd q 8888883
  let 44444444 = X
  ((x+1)*(2X+3)*(X-2)+ x-6)/ x^2
  by solving it we will get 2x-5 = 88888883
  
  ans for 1 is 444446
  lae x=22222
  ((x+2)*(2x+1)*(x-1) + 3x + 2)/x2 = 2x+2
  so 444446
  
• 12 years agoHelpfull: Yes(8) No(2)
• x=222222
  ((x+2)*(2x+1)*(x-1)+(3x+2))/x^2
  
  => ((2x^2 + 5x + 2)*(x-1)+(3x+2))/x^2
  => ((2x^3 + 5x^2 + 2x - 2x^2 - 5x -2)+(3x+2))/x^2
  => ((2x^3 + 3x^2 -3x -2) + (3x+2))/x^2
  => (2x^3 + 3x^2)/x^2
  => x^2(2x + 3)/x^2
  => 2x + 3
  => 2(222222)+3 = 444447
• 11 years agoHelpfull: Yes(6) No(0)
• 444447
  by calci
• 12 years agoHelpfull: Yes(5) No(11)