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The sequence is defined by A(1)=2 and A(n+1)=A(n)+2n What is the value of A(100)
(1)9902
(2)9900
(3)10100
(4)9904
Read Solution (Total 3)
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- 9902
A(100)=A(99)+2*99
same here
A(100)=A(1)+2*(1+2+3+.....+99)
A(100)=2+9900
A(100)=9902
ans is (1)9902 - 12 years agoHelpfull: Yes(12) No(2)
- A(100)= A(99)+2(99)
A(100)= A(98)+ 2(98)+2(99)
A(100)= A(97)+2(97)+2(98)+2(99)
||LY
A(100)= A(1)+ 2(1+2+3+4+.......97+98+99)
NOW; 1+2+3.......+97+98+99= 99(2+98)/2= 4950
(SUM OF AN A.P)
A(100)= 0+ 2(4950)= 9900 - 12 years agoHelpfull: Yes(2) No(13)
- a(1)=2
a(n+1)= a(n)+2n
a(2)= a(1)+4
a(3)=a(2)+6
a(4)= a(3)+8
.
.
.
a(100) = a(99)+198
adding R.H.S and L.H.S seperatly
we get
a(2)+a(3)+a(4)....a(100)= a(1)+a(2)+a(3)....a(99) + (4+6+8+10+....198)
thus
a(100)= a(1)+ 9898
a(100)= 2 +9898
a(100)= 9900
ans - 12 years agoHelpfull: Yes(1) No(5)
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