Sum of three positive even integers is 30 and their product is 960. Sum of the two smaller integers will be?

• let three even numbers is x,x+2,x+4then
  3x+6=30=>x=8 then series is 8,10,12 then product:8*10*12=960.
  small digit sum is:8+10=18
• 11 years agoHelpfull: Yes(7) No(1)
• 18
  
  Sum of three positive even integers is 30 ... 8+10+12
  and their product is 960-- 8*10*12
  . Sum of the two smaller integers will be 8+10=18
  
• 11 years agoHelpfull: Yes(3) No(1)
• let the 1st digit be x
  now x+(x=2)+(x+4)=30
  we get x=8
  then 8 +10=18
• 11 years agoHelpfull: Yes(3) No(1)
• three even no be (x+2),(x+4),(x+6)
  then there sum is
  (x+2)+(x+4)+(x+6)=30
  so x is 6
  sum of smaller no is (x+2)+(x+4)=6+2+6+4=18
• 11 years agoHelpfull: Yes(1) No(0)
• it hasn't been mentioned that the 3 integers are consecutive!
  >>so, since the '0' in '960' can only be present if AxBxC contains '10' as an integer. rest two integers' product has to be 96. 12x8 is the only possibility within the given constraints.
  thus, 8, 10, 12 are the integers and 18 is the total.
• 11 years agoHelpfull: Yes(0) No(0)
• ans=18
  hence numbers are 8,10,12
  8+10+12=30
  8*12*10=960
  
• 11 years agoHelpfull: Yes(0) No(0)