6 6 6

actual question is √(6+√(6+√6.....))

x=√(6+√(6+√6.....))
x^2=6+√(6+√(6+√6.....))
x^2=6+x
x^2-x-6=0
x=3
8 years agoHelpfull: Yes(6) No(3)
let x=√6+√6…….
x-√6=√6+√6…….
(x-√6)^2=(x)^2
x=√3/2
8 years agoHelpfull: Yes(5) No(8)
N*6^(1/2)
Were N is no. of times 6^(1/2) added
8 years agoHelpfull: Yes(1) No(0)
Let √6+√6+√6+...=x ---------(1)
if √6+ x =x (or)
√6+ √6=x-√6 both can be possible
after solving both equation u will get x=√6/2 or -√6/2.
same as RAMAKRISHNA VELAGA concept but both answers are possible and answer will be √6/2
8 years agoHelpfull: Yes(1) No(2)
for infinite series it can be written as √(6+x)=x
solving this equation we get x=3
8 years agoHelpfull: Yes(1) No(0)
7.347 its 3*1.414*1.732
8 years agoHelpfull: Yes(0) No(1)
multiple of 6 for even repetition and roots(square,cube,etc) of 6 for odd repetition....
8 years agoHelpfull: Yes(0) No(0)
√6=2.4494
√6+√6+√6=7.34845 (rounded-off)
8 years agoHelpfull: Yes(0) No(0)
does any1 tell me how to apply in google
7 years agoHelpfull: Yes(0) No(0)
Let √6+√6+√6+...=x ---------(1)
if √6+ x =x (or)
√6+ √6=x-√6 both can be possible
after solving both equation u will get x=√6/2 or -√6/2.
same as RAMAKRISHNA VELAGA concept but both answers are possible and answer will be √6/2
7 years agoHelpfull: Yes(0) No(0)

√6+√6+√6…….