√6+√6+√6…….

• √6(1+1+1+............)
  √6*∞= ∞
• 9 years agoHelpfull: Yes(7) No(4)
• actual question is √(6+√(6+√6.....))
  
  x=√(6+√(6+√6.....))
  x^2=6+√(6+√(6+√6.....))
  x^2=6+x
  x^2-x-6=0
  x=3
• 8 years agoHelpfull: Yes(6) No(3)
• let x=√6+√6…….
  x-√6=√6+√6…….
  (x-√6)^2=(x)^2
  x=√3/2
• 9 years agoHelpfull: Yes(5) No(8)
• N*6^(1/2)
  Were N is no. of times 6^(1/2) added
• 9 years agoHelpfull: Yes(1) No(0)
• Let √6+√6+√6+...=x ---------(1)
  if √6+ x =x (or)
  √6+ √6=x-√6 both can be possible
  after solving both equation u will get x=√6/2 or -√6/2.
  same as RAMAKRISHNA VELAGA concept but both answers are possible and answer will be √6/2
• 9 years agoHelpfull: Yes(1) No(2)
• for infinite series it can be written as √(6+x)=x
  solving this equation we get x=3
  
• 8 years agoHelpfull: Yes(1) No(0)
• 7.347 its 3*1.414*1.732
• 9 years agoHelpfull: Yes(0) No(1)
• multiple of 6 for even repetition and roots(square,cube,etc) of 6 for odd repetition....
• 9 years agoHelpfull: Yes(0) No(0)
• √6=2.4494
  √6+√6+√6=7.34845 (rounded-off)
• 8 years agoHelpfull: Yes(0) No(0)
• does any1 tell me how to apply in google
• 8 years agoHelpfull: Yes(0) No(0)
• Let √6+√6+√6+...=x ---------(1)
  if √6+ x =x (or)
  √6+ √6=x-√6 both can be possible
  after solving both equation u will get x=√6/2 or -√6/2.
  same as RAMAKRISHNA VELAGA concept but both answers are possible and answer will be √6/2
• 7 years agoHelpfull: Yes(0) No(0)