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Exam
Numerical Ability
Book contain 534 pages . how many times does 3 digit appear in page numbers ?
Read Solution (Total 2)
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- Pg 001 - 099 = 20 times (count it)
Pg 100- 199 = 20
Pg 200- 299 = 20
Hold on for pg 300- 399
Pg 400- 499 = 20
Pg 500 - 534 = 9
Pg 300= 1
Pg 301-310 = 11
Pg 311 - 320 = 11
Pg 321 - 330 = 12
Pg 341 - 350 = 11
Pg 351 - 360 = 11
Pg 361 - 370 = 11
Pg 371 - 380 = 11
Pg 381 - 390 = 11
Pg 391 - 399 = 11
Pg 331 - 340 = 20
(331,332,333,334,335,336,337,338,339,
340)
Total = 20+20+20+20+9+1+11+11+12+11+11+11+11+11+11+20= 210
In above by mistake counted 19 instead of 20. - 9 years agoHelpfull: Yes(1) No(0)
- 209 times 3 appear on page
Pg 001 - 099 = 20 times (count it)
Pg 100- 199 = 20
Pg 200- 299 = 20
Hold on for pg 300- 399
Pg 400- 499 = 20
Pg 500 - 534 = 9
Pg 300= 1
Pg 301-310 = 11
Pg 311 - 320 = 11
Pg 321 - 330 = 12
Pg 341 - 350 = 11
Pg 351 - 360 = 11
Pg 361 - 370 = 11
Pg 371 - 380 = 11
Pg 381 - 390 = 11
Pg 391 - 399 = 11
Pg 331 - 340 = 19
Total = 20+20+20+20+9+1+11+11+12+11+11+11+11+11+11+19= 209 - 9 years agoHelpfull: Yes(0) No(0)
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