Consider all permutations of digits 1,2&3.We will say that a hit has been scored if at least one digit occurs in its proper position in the permutation.If 1 occurs in the first position or 2 in the second position or 3 in the 3rd position in how many ways of these permutations is a hit scored?
(a)4(b)1(c)2(d)(3

• the answer is 4..
  
  as it is written If 1 occurs in the first position OR 2 in the second position OR 3 in the 3rd position
  1 occurs at the first position only twice i.e. (123) and (132)
  whereas
  2 also occurs at the second position twice only i.e. (123) and (321)
  whereas
  3 also at the right position dat is third place only twice i.e. (123) and (213)
  so the hit will only be scored when it will be
  (123),(132),(213),(321)
  so the answer is 4
• 11 years agoHelpfull: Yes(12) No(1)
• 123
  132
  231
  213
  312
  321
  SO ans 4
• 11 years agoHelpfull: Yes(10) No(3)
• TOTAL PERMUTATIONS={1,2,3}{1,3,2}{2,1,3}{2,3,1}{3,1,2}{3,2,1}
  SO ITS ANSWER=4
• 11 years agoHelpfull: Yes(3) No(1)
• boss they are asking atleast one not asking exactly one
  so the answer is 4+5+6=15
• 11 years agoHelpfull: Yes(1) No(4)