implement adding twounsighned numbers without using + or ++

• suppose two numbers a and b then a-(-b)=sum of a and b;
  
• 11 years agoHelpfull: Yes(10) No(4)
• As we know a^2-b^2= (a+b)(a-b)
  
  so a+b= (a^2-b^2) / (a-b)
  
  and 2nd one is
  int add (int a, int b)
  {
  int c, d;
  if (b == 0)
  {
  return a;
  }
  
  c = a ^ b; // xor takes sum
  d = a & b; // collect carry;
  d = d
• 11 years agoHelpfull: Yes(8) No(2)
• if x and y are the two unsigned numbers, then
  x+y = (x*x-y*y)/(x-y)
  eg: x=5 and y=2
  5+2=7
  (x*x-y*y)/(x-y)=(5*5-2*2)/(5-2)
  =(25-4)/3
  =21/3
  =7
  
• 11 years agoHelpfull: Yes(4) No(0)
• use or between 2 unsigned numbers
• 9 years agoHelpfull: Yes(1) No(0)
• 1. Take first number, multiply it with -1.
  2. Subtract second number from step 1.
  3. Multiply the result with -1 again.
  2 numbers are added without using + or ++.
• 7 years agoHelpfull: Yes(1) No(0)
• Sum of two bits can be obtained by performing XOR (^) of the two bits. Carry bit can be obtained by performing AND (&) of two bits
  
  int Add(int x, int y)
  {
  if (y == 0)
  return x;
  else
  return Add( x ^ y, (x & y)
• 10 years agoHelpfull: Yes(0) No(0)
• Perform logical OR operation.
• 9 years agoHelpfull: Yes(0) No(0)
• #include
  
  int Add(int x, int y)
  {
  // Iterate till there is no carry
  while (y != 0)
  {
  
  int carry = x & y;
  
  // Sum of bits of x and y where at least one of the bits is not set
  x = x ^ y;
  
  // Carry is shifted by one so that adding it to x gives the required sum
  y = carry
• 7 years agoHelpfull: Yes(0) No(0)
• use or between 2 unsigned numbers
• 7 years agoHelpfull: Yes(0) No(0)
• we can add two unsigned numbers without using +or ++
  for ex :
  import java.util.scanner
  class Add
  {
  public static void main(String[] arg)
  {
  int a,b,c;
  Scanner sc=new Scanner(System.in);
  System.out.println("Enter first number");
  a=sc.nextInt();
  System.out.println("Enter second number");
  b=sc.nextInt();
  c=addition(a,b);
  System.out.println(" Addition of two numbers is : "+c);
  }
  static int addition(int x,int y)
  {
  return x+y;
  }
  }
• 4 years agoHelpfull: Yes(0) No(0)