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Numerical Ability
Permutation and Combination
How many 5 digit numbers can be formed with using 1,2,3,4,5,6,7,8 digits?
Read Solution (Total 40)
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- 8*8*8*8*8=32768
as unit place is filled in 8 ways .... and so tens place.. and so on.....
so , solution is 8^5=32768(universal law of counting) - 12 years agoHelpfull: Yes(100) No(19)
- if repeatation allowed then 8^5
else if not allowed then 8*7*6*5*4 - 11 years agoHelpfull: Yes(77) No(5)
- no of ways = 8C5
8*7*6/3*2 = 8*7 = 56
answer = 56 - 12 years agoHelpfull: Yes(20) No(70)
- 8p5=8!/(8-5)!=6720
There 6720 numbers be formed - 12 years agoHelpfull: Yes(20) No(12)
- If repition allowed : 8*8*8*8*8
8^5
repition not allowed:8*7*6*5*4=6720 - 11 years agoHelpfull: Yes(11) No(1)
- if it is repeated 5^8 else if it is not repeated 8*7*6*5*4=8!/5! :)
- 12 years agoHelpfull: Yes(10) No(2)
- we have to select 5 digits from the given 8 digits therefore 8c3=56
- 12 years agoHelpfull: Yes(6) No(5)
- 8*8*8*8*8=32768
- 11 years agoHelpfull: Yes(5) No(1)
- 8*8*8*8*8=32768
- 11 years agoHelpfull: Yes(4) No(0)
- if repetition is allowed then ans is 8*8*8*8*8 = 32768
if repetition is not allowed then ans is 8*7*6*5*4 = 6720 - 11 years agoHelpfull: Yes(3) No(0)
- for the 1st digit we hav 8 way ,for 2nd digit we hav 8 way and so on then the ans will be =8pow(5)(here repition is allowed)
- 11 years agoHelpfull: Yes(2) No(0)
- 8^5=32768
A/C to law of aounting - 11 years agoHelpfull: Yes(2) No(0)
- 8^8 =32768 is right
- 11 years agoHelpfull: Yes(1) No(5)
- According to permutation it would be 8p5 and when we solve it it would be (8!/3!) then the ans is 6720
- 11 years agoHelpfull: Yes(1) No(2)
- 8p5=8!/(8-5)!=6720
- 11 years agoHelpfull: Yes(1) No(0)
- Total 8 digits so, we need 5 digit numbers then they are not specified any condition here so assume repetation allowed,
then ans will be 8^5=32,768. - 11 years agoHelpfull: Yes(1) No(0)
- 8p5= 8!/(8-5)!
= 8*7*6*5*4/3*2
= 1120. - 11 years agoHelpfull: Yes(1) No(2)
- sorry abt the earlier post,
the correct calculation is :
8p5 =8!/(8-5!)
=8*7*6*5*4*3*2/3*2
=6720 - 11 years agoHelpfull: Yes(1) No(0)
- if repeatation allowed then,ans=8^5;
if repeatation not allowed, then ans=8*7*6*5*4=6720; - 11 years agoHelpfull: Yes(1) No(0)
- 8*8*8*8*8=32768
- 10 years agoHelpfull: Yes(1) No(0)
- according to permutation and combination
8c5=8!/(8-5)!
=8!/3!
= 8*5*6!/3*2!
=56 - 9 years agoHelpfull: Yes(1) No(0)
- 1234(5678)
5 digit=5p5=120
4 digit=4p4=24
total combination=120*24=2880 - 11 years agoHelpfull: Yes(0) No(5)
- 6720
how many ways we can arrange 8 digits in 5 positions
8P5=8!/(8-3)! - 11 years agoHelpfull: Yes(0) No(5)
- 8^8
because there is no repeation
- 11 years agoHelpfull: Yes(0) No(6)
- since with repetition the the no. of ways a 5 digit number formed is 8*8*8*8*8
- 11 years agoHelpfull: Yes(0) No(0)
- if repeatation is not allowed then
ans is=8*7*6*5*4
- 11 years agoHelpfull: Yes(0) No(0)
- 8C5*5!
no of ways 5 no can be selected=8C5
no of ways it can be arranged=5! - 11 years agoHelpfull: Yes(0) No(0)
- 8p5 =8*7*6*5
- 11 years agoHelpfull: Yes(0) No(1)
- ----- i.e 5 spaces, so r=5
no. of digits n=8
there is a direct formula=n^r=8^5=32768 - 10 years agoHelpfull: Yes(0) No(0)
- 8P5 (Because its a arrangement so we can solve it through Permutation)
8*7*6*5*4=6720 - 10 years agoHelpfull: Yes(0) No(0)
- arrangement can be made as 8p5=336
- 10 years agoHelpfull: Yes(0) No(0)
- 2*root(2):1
- 10 years agoHelpfull: Yes(0) No(1)
- ans is 4*5*6*7*8=6720
and sorry for previous ans that ans is for #M40007881. - 10 years agoHelpfull: Yes(0) No(0)
- permutation& combination then
8p5=8*7*6*5*4=6720 Ans - 10 years agoHelpfull: Yes(0) No(0)
- 8^5 if repetition is allowed
8*7*6*5*4 if repetition is not allowed - 10 years agoHelpfull: Yes(0) No(0)
- 6720
8*7*6*5*4=6720 - 10 years agoHelpfull: Yes(0) No(0)
- solution:
8^5=32768 ans - 10 years agoHelpfull: Yes(0) No(0)
- 8C5=8!/3!=5760
- 10 years agoHelpfull: Yes(0) No(0)
- (8c5)+8=336+8=344
+8 is for combination formed by a single digit - 10 years agoHelpfull: Yes(0) No(1)
- 8C5 = !8/!5*!8-5= 8*7*6/3*2=8*7=56
- 8 years agoHelpfull: Yes(0) No(0)
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