1. Rahul can finish one-fifth of hhis homework in one hour.Neha can finish three-seventh of her homework in one hout thirty minutes and riya can finish three fourth of her homework in three hours thirty minutes.If all of them start their homework at 12:00pm and can go to play as soon as they all finish their homework,when can they start to play,if they take a break at 3:30pm for thirty minutes?
a. 5.00pm
b. 5:30pm
c. 4.40pm
d. 6.30pm
e. 3.30pm

2. My computer needs upgradation since it.... a very old version
1. is
2. was
c. were
d. must

3.salim could not make it to the party as he---- to finish his assignment
a. has
b.had
c. have
d. went

4.Funds are scarce,so.... are needed to rebuild homes destroyed by the folld
a. patience b.volunteers c.workers d.materials

5. simplify (144^-3/2)^-1/6
a. 2root3
b.6
c.3root2
d. 4

• 1)b
  2)1
  3)d
  4)d
  5)a
  
  Solution 1: Let the work be 1
  Then Rahul do 1/5 work in 60min
  So Rahul do 1 work in 300 min
  
  Then Neha do 3/7 work in 90min
  So Neha do 1 work in 210min
  
  Then Riya do 3/4 work in 210min
  So Riya do 1 work in 280 min
  
  By 300min i.e 5hr all will complete their work so
  12-1,1-2,2-3,3-3:30, 4-4:30,4:30-5:30
  By 5:30 they all go to play
  
  Solution 5: ((1/144)^3/2)^-1/6
  ((1/12)^3)^-1/6
  ((1/(12*12*12))^-1/6
  (12*12*12)^1/6
  2root3
• 9 years agoHelpfull: Yes(6) No(9)
• 2)a
  3)a
  4)b
• 8 years agoHelpfull: Yes(0) No(0)
• http://www.geekplacement.com/2015/06/amcat-aspiring-minds-previous-questions.html
  
  3. A
• 6 years agoHelpfull: Yes(0) No(0)
• Answer:
  
  5:30 PM
  
  Step-by-step explanation:
  
  Rahul 1/5 = 1 hr
  
  Rahul work = 5 hr
  
  Nehs 3/7 = 1.5 hr
  
  Neha Work  = 7*1.5/3
  
  Riya 3/4 = 3.5 hr = 3 hours 30 mintes
  
  Riya work = 3.5*4/3 = 14/3 = 4 hours 40 minutes
  
  max time taken by Rahul = 5 hr
  
  30 minutes break taken
  
  so they can start after 5 hour 30 minute
  
  5:30 PM
• 5 years agoHelpfull: Yes(0) No(0)
• 2. Salim could not make it to the party as he was to finish his assignment
• 4 years agoHelpfull: Yes(0) No(0)