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simple proof for e^o=1

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e^0=e^(n-n)=(e^n)/(e^n)=1
12 years agoHelpfull: Yes(15) No(0)

e^(ja)=cos(a) + jsin(a)
Let a=0;
e^(0)=cos(0) +jsin(0)
e^(0)=1+j.0
e^0=1
12 years agoHelpfull: Yes(10) No(0)

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