a hollow cube of size 5cm is taken,with a thickness of 1cm.It is made of smaller cubes of size 1cm.If 1 face of the outer surface of the cube are painted,totally how many faces of the smaller cubes remain unpainted?

• volume of cube of size 5cm=5*5*5=125
  to make this cube hollow we hv to remove 9*3=27cubes
  so,125-27=98
  for the 6 faces of cube total cubes 98*6=588
  1 face of cube contain 25 cubes.
  so,the faces tht remain unpainted'll be 588-25=563
  
• 13 years agoHelpfull: Yes(11) No(2)
• the answer for this is 563
  
  volume of solid cube- 5*5*5= 125 cu cm (so number of cubes is 125 each of 1 cu cm.)
  
  Now remove the cubes to make it hollow = 5*5*5 -3*3*3 =98
  
  Hence there are 98 small cubes(side=1cm) in hollow Cube (side=5cm)....
  
  Each cube has total of 6 faces, total faces = 98*6 =588
  
  But the cube(side =5cm) is painted from outside, hence number of painted of painted faces=1, each face has 25 faces of small cubes, hence ans is
  
  588-25= 563
• 13 years agoHelpfull: Yes(5) No(0)
• no. of cubes=125-27=98
  total no. of faces=98*6=588
  unpainted faces=588-25=563
• 13 years agoHelpfull: Yes(2) No(1)