exam Maths Puzzle Numerical Ability

divide 5+ 3j over 2 + j I did the next step and came up with
10 - j5 + j6 -1 over 2^2 - (j^2)^2 I don't know if I did that right and not sure what to do next.

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Please help me simplify.
x^2+6x-27/3-x. The book says the answer is -(x+9)
twice the lesser of two consecutive intergers is 12 less than 3 times the greater interger find the lesser interger