CAT
Exam
24+35=28
15+49=24
69+37=50
27+48=
Read Solution (Total 2)
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- sum of 24 and 35 is 60; now 60-{8*(units digit of the smallest number b/w 24 and 35)}=60-(8*units digit of 24)=60-(8*4)=60-32=28--->24+35=28
sum of 15 and 49 is 64; now 64-{8*(units digit of the smallest number b/w 15 and 49)}=64-(8*units digit of 15)=64-(8*5)=64-40=24---->15+49=24
sum of 69 and 37 is 106;now 106-{8*(units digit of the smallest number b/w 69 and 37)}=106-(8*units digit of 37)=106-(8*7)=106-56=50---->69+37=50
sum of 27 and 48 is 75; now 75-{8*(units digit of the smallest number b/w 27 and 48)}=75-(8*units digit of 27)=75-(8*7)=75-56=19------->27+48=19
Hence Answer is 19 - 12 years agoHelpfull: Yes(4) No(9)
- first off all your question is wrong
15 + 49 = 24 thats wrong pls check
the answer is:
27+48=42
add the single digits and double them
2+7+4+8=21 * 2 = 42
24 + 35 = 28
2+4+3+5=14 * 2 = 28
69+37=50
6+9+3+7=25 * 2 = 50
- 12 years agoHelpfull: Yes(2) No(1)
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