a bottle contains 3/4 of milk and the rest water . what quantity of the mixture must be taken away and replaced by equal quantity of water so that mixture has half milk and half water?

• initially milk=3/4 so water= 1-3/4 =1/4
  let x litre be taken
  so rest amount of milk in bottle=(3/4)-(3x/4) =(1-x)*(3/4)
  so rest amount of water in bottle=(1/4)-(x/4) =(1-x)*(1/4)
  now amount is replaced by water
  so now water in bottle=(1-x)*(1/4)+x
  from question ratio milk:water becomes 1:1
  (1-x)*(1/4)+x = (1-x)*(3/4)
  1-x+4x=3-3x
  1+3x=3-3x
  6x=2
  x=1/3
  so 1/3 of bottlte mixture must be replaced by water to get ration of 1:1.
• 11 years agoHelpfull: Yes(20) No(1)
• Ans 1/3
  Milk:Water=3:1 in % Ratio=75:25
  For the mixture to contain half milk and half water,milk should be 50%
  For this 1/3 quantity of mixture is to be replaced by water
  New quantity of Milk(75- 75/3 =50) and Water (25- 25/3 + 25+ 25/3=50)
• 11 years agoHelpfull: Yes(9) No(2)
• its very simple ....milk is 3/4 thats's mean 75 % is milk and 1/4 is water that is 25 % water
  we have to make 50-50 solution so if we add 25% water in the water part and same quantity is reduced from the milk part so that the ration become 50- 50
  25% of 75 is known is 1/3
  so answer is 1/3
• 8 years agoHelpfull: Yes(3) No(0)
• milk=3/4
  water =1/4
  let x lt taken
  rest amount of milk=3/4- 3x/4=3/4*(1-x)
  rest amount of water=1/4*(1-x)
  now equal amount of water is replaced by x lt
  amount of water=(1-x)*1/4+x
  new ratio=1:1
  (1-x)*1/4+x=(1-x)*3/4
  by solving we get x=1/3
  so 1/3 of bottle mix must be replaced by water to get ratio =1:1
• 11 years agoHelpfull: Yes(1) No(1)