A Gambler starts playing a game in a casino. In the first round he doubles the amount with
him and gives away Rs. 2P to his friend. In the second round he triples the amount left with
him and gives away Rs. P to his friend. In the third round he quadruples the amount left with
him and gives away Rs. 3P to his friend and is left with Rs. 60. In all if he gave away Rs. 360 to
his friend, with what amount did he start playing ?
a. Rs 40 b. Rs. 60 c. Rs.80 d. Rs. 100

• let he starts with x
  after 1st round
  amount left (2x-2p)
  after 2nd round
  amount left {3(2x-2p)-p}
  after 3rd round
  amount left [4{3(2x-2p)-p}-3p]-------------(1)
  from question
  amount given to his friend 2p+p+3p=360
  so p=60
  put this value in equation (1)
  and solving we get x=80 Rs
• 11 years agoHelpfull: Yes(2) No(0)
• gambler starts with x
  
  after 1st round =2x-2p (2p is given to friend)
  
  after 2nd round =3(2x-2p)-p (p is given to friend)
  =6x-7p
  
  after 3rd round =4(6x-7p)-3p (3p is given to friend)
  =24x-31p
  
  given sum given to frnds is p+2p+3p=360=>p=60
  
  and also 24x-31p=60
  24x=32*60 (p=60)
  x=80
  
• 11 years agoHelpfull: Yes(1) No(0)
• 4(6x-7p)-3p=60 and p+2p+3p=360
• 9 years agoHelpfull: Yes(0) No(0)