1 t0 44 like 1234567891011121314151617181920......424344
what is remainder whn divided by 45??

• Ans is 4
  division by 45 means division by 9 and 5(9*5)
  for divsion by 5 ,last digit either should be 0 or 5
  and by 9 ,sum of digit should be divided by 9.
  as there is no remainder when division by 9.but on division by 5 ,4 is remainder.
  so answer is 4.
• 12 years agoHelpfull: Yes(32) No(23)
• Let N = 1234567891011121314151617181920......424344
  
  Remainder when N is divided by 5 is 4.  So N = 5K + 4 .....(1)
  
  Remainder when N is divided by 9 is Sum of the digits of N divided by 9. We know that
  
  1+2+3+...44 = 990 Which gives digit sum as 9. So remainder when N is divided by 9 is 0.
  
  So N = 9L .....(2)
  
  Equation (1) and (2) we 9L = 5K + 4
  
  For K = 1 this equation gets satisfied. So least possible number satisfies the condition is 9
  
  So The general format of N = w(LCM of (9, 5)) + Least number satisfies the condition.
  
  So N = w.45 + 9
  
  When N is divided by 45, we get 9 as remainder.
• 9 years agoHelpfull: Yes(9) No(3)
• sum of n natural no is=n*n+1/2,so n=44,44*45/2=22*45=990den 990/45 den rem is 0
• 12 years agoHelpfull: Yes(7) No(27)
• rem=9
  2511/45=36
  1314/45=9--------------36/4
  1224/45=9---------------36/4
• 12 years agoHelpfull: Yes(7) No(7)
• Let N = 1234567891011121314151617181920......424344
  Remainder when N is divided by 5 is 4.  So N = 5K + 4 .....(1)
  Remainder when N is divided by 9 is Sum of the digits of N divided by 9. We know that 1+2+3+...44 = 990 Which gives digit sum as 9. So remainder when N is divided by 9 is 0.
  So N = 9L .....(2)
  Equation (1) and (2) we 9L = 5K + 4
  For K = 1 this equation gets satisfied. So least possible number satisfies the condition is 9
  So The general format of N = w(LCM of (9, 5)) + Least number satisfies the condition.
  So N = w.45 + 9
  When N is divided by 45, we get 9 as remainder.
  
• 9 years agoHelpfull: Yes(1) No(2)
• N = w(LCM of (9, 5)) + least.......need explanation, please help
• 9 years agoHelpfull: Yes(1) No(1)