2^74+2^2058+2^2n what is d value of n to make it perfect square???

• 2^74+2^2058+2^2n
  = (2^37)^2+2*(2^37)*( 2^2020)+2^2n
  
  so n should be equal to 2020 for making 2^74+2^2058+2^2n a perfect square.
• 12 years agoHelpfull: Yes(22) No(5)
• dis problem is solved by converting the given statement into a^2+2ab+b^2 format then we will get the d value
• 12 years agoHelpfull: Yes(7) No(1)
• 2^74+2^2058+2^2n
  (2^37)^2+ 2*(2^37)*(2^2020)+2^2n
  if n=2020 den it is perfect square
• 11 years agoHelpfull: Yes(1) No(0)
• 2^74+2^2058+2^2n
  = (2^37)^2+2*(2^37)*( 2^2020)+2^2n
  
  so n should be equal to 2020 for making 2^74+2^2058+2^2n a perfect square.
• 7 years agoHelpfull: Yes(0) No(0)