Q. A train covers the distance d between two cities in h hours arriving J. hours late. What rate would permit the train to arrive on schedule?

• train takes time of h hours and it is late by j hours so it should have made journey in h-j hour
  so the rate should be: distance/time = d/(h-j)
• 11 years agoHelpfull: Yes(7) No(1)
• Speed = Distance/Time
  Distance = d
  Time taken = h
  But train is late by 2 hours
  So, the time taken should have been h-2
  ! stands for division (assumption)
  So, Speed required to be on time = d/(h-2)
  
• 9 years agoHelpfull: Yes(2) No(1)
• train reached the station late for j hours so actual time taken by the train is h+j
  speed=distance/time
  =d/(h+j)
• 8 years agoHelpfull: Yes(2) No(2)
• distance =d;
  time taken=h;
  but train late by j hours
  there fore speed required to be on time=d/(h-j)
• 7 years agoHelpfull: Yes(1) No(0)
• Can you please post some more ITC Infotech questions which you had in the aptitude test. ITC Infotech will visit us on the 16th this month. Please help.
  
• 11 years agoHelpfull: Yes(0) No(4)