TCS
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Numerical Ability
Permutation and Combination
for a set of 5 true or false questions,no student has written all the correct answers and no two students have given the same sequences of answers.what is the maximum number of students in the classes for this to be possible?
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- number of ways to arrange T or F for five questions is 2^5=32
no student gave correct answer.. so 32-1= 31.
hence max students are 31 :) - 12 years agoHelpfull: Yes(41) No(2)
- 5 questions can be T or F.. ie 5 questions,each can either of 2 values ..so 2^5=32..
- 12 years agoHelpfull: Yes(2) No(12)
- Reading this the first thing, which is obvious, that there is only one possible sequence, which none of the children answered. Now if we find the no. of possible sequences, subtract one from it, we will get our answer.
total possible sequences= 2^5=32
correct answer sequence=1
wrong answer sequences=32-1=31 - 8 years agoHelpfull: Yes(0) No(0)
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