TCS
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Numerical Ability
Averages
how many three digit odd numbers can be formed from the digits 1,2,3,4,5 and 6 when
(a) repetition is not allowed
(b) repetition is allowed
Read Solution (Total 2)
-
- when repetition is not allowed
last digit can be 1,3,5 ( 3 ways ) 1st digit can be 5 ways and 2nd digit can be 4 ways
total 3*5*4=60 ways
when repetition allowed
last digit can be filled in 3ways and
rest 2 digits can be filled in 6 ways each
so total number of ways=3*6*6=108 - 12 years agoHelpfull: Yes(34) No(2)
- (a) when repetition is not allowed and number to be odd
last digit will always have= 1,3,5 = 3 ways
rest digit can be filled in = 5 ways first digit and 4 ways last digit
tottal= 3 x 5 x 4 = 60 numbers
(b)when repetition is allowed and number to be odd
last digit will always have= 1,3,5 = 3 ways
rest digit can be filled in = 5 ways first digit and 5 ways last digit
total = 5 x 5 x 3 = 75 numbers - 12 years agoHelpfull: Yes(0) No(27)
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