a committee of 5 persons is to be formed from a group of 6 gentlemen and 4 ladies.the no. of ways in which the committe contains atleast one lady.

• possible selections are
  1 lady and 4 gentlemen=4C1*6C4=60 WAY
  2 lady and 3 gentlemen=4C2*6C3=120 WAY
  3 lady and 2 gentlemen=4C3*6C2=60 WAY
  4 lady and 1 gentlemen=4C4*6C1=6 WAY
  SO POSSIBLE NO OF WAYS=60+120+60+6=246 WAYS
• 12 years agoHelpfull: Yes(31) No(0)
• 4c1*6c4+4c2*6c3+4c3*6c2+4c4*6c1
  ans is 60+120+60+6
  ans is 246 ways
• 12 years agoHelpfull: Yes(15) No(0)
• another way is total possibilities-no lady
  (10c5)-(6c5)=246
  10c5----->total no of possibilities
  6c5-------->all are selected from men(no ladies)
• 12 years agoHelpfull: Yes(13) No(1)
• total 10 person r there
  so we can select 5 out of them in 10C5 ways
  all 5 are male is 6C5
  
  atleast 1 female= total-all male = 10c5-6c5=246
• 11 years agoHelpfull: Yes(2) No(1)
• Can't this be done like that,
  If one lady should at least be there then let place it in one of the 5 positions of the committee, now there are 9 people for 4 positions hence 9C4 and in each combination one lady will be there?
• 8 years agoHelpfull: Yes(0) No(0)