TCS
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Numerical Ability
Permutation and Combination
an examinee is required to answer 6 questions out of 12 questions which are divided into two groups each containing six questions and he is not permitted to answer more than four questions from any group.in how many ways he can answer the 6 questions?
Read Solution (Total 6)
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- two sets have 6 questions each
to satisfy the condition given he must attempt (2,4)or(3,3)or(4,2)
selecting 2 out of 6 from 1st set & 4 out of 6 from 2nd set=6c2&6c4
so total=6c2*6c4 ways if(2,4)
similarly if (3,3) and (4,2) it has 6c3*6c3 ways and 6c4*6c2
total 6c2*6c4+6c3*6c3+6c4*6c2=850 - 12 years agoHelpfull: Yes(54) No(0)
- sry at last d ans is 850ways
- 12 years agoHelpfull: Yes(7) No(1)
- the way he can select group = 2C1 = 2
for each goup he can answer in this way= 6C3 x 6C3 OR 6C4 x 6C2 or 6C2 x 6c4
so total ways = 2 x {6C3 x 6C3 + 6C4 x 6C2 + 6C2 x 6c4}
=1700 ways - 12 years agoHelpfull: Yes(4) No(32)
- ans frm the 2 sets mst b in d form:(2,4)(3,3)(4,2)
so,no. of ways shud b:6c2*6c4+6c3*6c3+6c4*6c2=50 ways - 12 years agoHelpfull: Yes(1) No(12)
- Ans =450
(6c2*6c4)+(6c4*6c2)
450 - 6 years agoHelpfull: Yes(0) No(2)
- 12C6 =1144
From condition possible ways are 6c2*6c4+6c3*6c3+6c4*6c2=850
now 1144-850=284 - 6 years agoHelpfull: Yes(0) No(2)
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