Q. There are two machines X and Y. X produces 100X /min and takes rest of 5 min to clean after 1000X. And Y produces 75Y/min and takes 10 min rest after a production of 1500Y. What will be minimum time after which 9000 pair of X,Y will be produced.

Option
a) 135
b) 130
c) 170
d) 180

• 170
  the time taken by x to produce 9000 of x=9*10 min+(9-1)*5 min=130 min
  the time taken by y to produce 9000 of y=20*6+(6-1)*10 min=170 min
  so to create the pair of 9000 of x,y is 170 min
• 11 years agoHelpfull: Yes(17) No(10)
• For machine X
  100 X -> 1 min
  1000 X -> 10 min + 5 min clean = 15 min
  So, 9000 X -> 15*9 = 135 min
  But the last 5 min would be for cleaning
  So, 9000 X can be produced by X in 130 min
  
  For machine Y
  75 Y -> 1 min
  So, 1500 Y -> 20 min + 10 min rest = 30 min
  So, 9000 Y -> 30*6 = 180 min
  But the last 10 min would be for rest. So, 9000 Y can be made in 170 min
  
  Desired Answer = Max(min(X,Y)) = Max(130,170) = 170 min
• 11 years agoHelpfull: Yes(14) No(6)
• answer 170
• 9 years agoHelpfull: Yes(1) No(0)
• y will required 180 mins and x will required 135 but the minimum time will be 180mins.
• 8 years agoHelpfull: Yes(1) No(3)