The NUmber when divided by 2,3,4,5,6 gives a reminder of 1...But when divided by 7 it gives a reminder of 0..what is That NUmber?

• LCM = 60
  for remainder 1 = 60+1= 61 (not divisble by 7)
  for remainder 1 = 60 x 2 +1= 121 (not divisble by 7)
  for remainder 1 = 60 x 3 +1= 181 (not divisble by 7)
  for remainder 1 = 60 x 4 +1= 241 (not divisble by 7)
  for remainder 1 = 60 x 5 +1= 301 ( divisble by 7) ans
  
• 11 years agoHelpfull: Yes(2) No(0)
• simple trick:
  take lcm of 2,3,4,5,6 it is 60.
  then required no must be either 60+1 or 60n+1 where n=1,2,3....
  so put n=8 .....720+1=721 is the answer....
• 11 years agoHelpfull: Yes(1) No(0)
• 301,
  it is an odd since it is divided by 1 and leaves remainder 1
  its last digit should be 1 or 6 since it is divided by 5 leaving remainder 1 but it iss odd number .So its last digit is 1
  number divided by 4 and has remainder 1 comes in series of 21,41,61,81.....
  and number divided by 6 and has remainder 1 satisfying above conditions come in series as 31,61,91,121...,
  in matching them conditions for 4 and 6 repeat at series of 61,121,181,241..,
  when this series divided by 7 we get remainders 5,2,6,3,0 ( gap of 4)
  so its solution will be 301( 5th number of series 61,121,181,241,301)
• 11 years agoHelpfull: Yes(0) No(1)