Two cubes each with side b are joined to form a cuboids. What is the surface area of this cuboids?

(a)12b^2 (b)10b^2 (c)6b^2 (d)4b^2

• ans is 10 b^2
  
  l=2b; b=b; h=b;
  
  surface area=2*(lb+bh+hl)
  =2*(2b^2+b^2+2b^2)
  =10 b^2
• 13 years agoHelpfull: Yes(3) No(0)
• (b)10b^2
  surface area of each cube = 6b^2
  when joined surface area = 6b^2 + 6b^2 - 2b^2
  so surface area of cuboid = 10b^2
• 13 years agoHelpfull: Yes(2) No(0)
• (b)10b^2
  
  surface area of each cube = 6b^2
  when joined then surface area = 6b^2 + 6b^2 - 2b^2
  so surface area of cuboid = 10b^2
• 13 years agoHelpfull: Yes(2) No(0)