At 12.00 hours Jake starts to walk from his house at 6 kms an hour. At 13.30 hours, Paul follows him from Jake’s house on his bicycle at 8 kms per hour. When will Jake be 3 kms behind Paul?

• sorry guys i din't read question properly....... :(
  
  jake has covered 9 km till 13.30
  and he has be 3 km behind paul so net distance= 9+3 = 12km
  relative speed= 2km/h
  therefore time = 12/2 = 6 hrs
  i.e 13.30+ 6 = 19.30hrs(ans)
• 12 years agoHelpfull: Yes(53) No(8)
• at 1430 jake travels 15km from his house and paul will be 8km
  at 1530 jake:21km paul:16km
  at 1630 jake:27km paul:24km
  so at 1630 paul will be 3km behind jake ans is 1630
• 12 years agoHelpfull: Yes(20) No(16)
• at 16.30
  as at 13.30 jake covered 9km while paul covered 0 in total.
  at 14.30 jake covered 15km while paul covered 8km in total.
  at 15.30 jake covered 21km while paul covered 16km in total.
  at 16.30 jake covered 27km while paul covered 24km in total.
• 12 years agoHelpfull: Yes(16) No(5)
• ans is 19:30.
• 12 years agoHelpfull: Yes(10) No(5)
• First ,let us calculate the time at which Paul catches Jake...
  To catch Jake,both has to cover equal distance...
  6*x=8*(x-3/2),where x is the time taken from 12:00 hrs at which paul overtakes jake
  x=6 hrs from 12 i.e 18:00 hrs
  At 18:00 hrs both are at same point...
  Next,we have to take the difference of distance b/w the two as 3km
  therefore,8(x)-6(x)=3,where x is the time taken from 18:00 hrs
  Hence x=1hr 30 minutes
  Therfore total time taken=18+1hr 30min=19:30
• 12 years agoHelpfull: Yes(10) No(2)
• jake has covered 9 km till 13.30
  relative speed= 2km/h
  now paul follows and has to cover 9-3= 6km distance with relative speed 2km/hr
  therefore time = 6/2= 3hr = 13.30+3= 16.30hr(ans)
• 12 years agoHelpfull: Yes(7) No(14)
• sorry guys the ans is 1930
  at 1930 paul covered 48km and jake is 45km
• 12 years agoHelpfull: Yes(2) No(2)
• after 6hour from 13.30 that means at 19.30 hours jake will be behind 3km from pauls
• 12 years agoHelpfull: Yes(2) No(1)
• Jake starts at 12 pm with 6 kmph. Hence till 1.30 pm he will cover 9 km. Now at 1.30 pm Paul starts with 8 kmph, i.e. with 4 km per half an hour. When Paul starts, he and Jake are already 9 km apart. Now, at 2 pm, Paul will cover 4 km and Jake 3 km more than previous, i.e. total 12 km and now they are 8 km apart. Proceeding this way,taking into account half hourly calculations,we get, the following table,
  Name 2:30 pm 3:00 pm 3:30 pm 4:00 pm 4:30 km
  Jake 15 km 18 km 21 km 24 km 27 km
  Paul 8 km 12 km 16 km 20 km 24 km
  Thus, answer is 4:30 pm as 27-24=3km.
• 12 years agoHelpfull: Yes(2) No(2)
• it is 19.30 hrs..because he is asking when will jake be 3 km behind paul..not paul is 3km behind jake, at 16.30 paul is 3 km behind jake..answer: 19:30 hrs
• 12 years agoHelpfull: Yes(1) No(0)
• 4:30(16:30) is the correct answer
  
• 12 years agoHelpfull: Yes(0) No(6)
• Jack Paul
  1.30 9 kms 0 km
  2.00 12 4
  2.30 15 8
  3.00 18 12
  3.30 21 16
  4.00 24 20
  4.30 27 24
• 9 years agoHelpfull: Yes(0) No(0)
• ans will be 7:30 when the paul start follow the jake at that time jack will rich to the 9 kms so at 7:30 jack will be 3 kms behind paul
• 8 years agoHelpfull: Yes(0) No(0)
• The correct answer must be 19:30 hrs
• 7 years agoHelpfull: Yes(0) No(0)
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  anjumbarbhuiya3913
  08.08.2018
  Math
  Secondary School
  +13 pts
  Answered
  at 12:00 hours jake starts to walk from his house at 6 km an hour. at 13:30 hours paul follows him from jake???s house on his bicycle at 8 km per hour. when will jake be 3 km behind paul?
  
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  By the time P starts J is 1.5 hr x 6 = 9 km away from his house.
  
  J is 3 km behind when P is 3 km ahead of him.
  
  ie.,
  
  P has to cover 12 km.
  
  So,
  
  He takes 12 / (8 - 6) = 6 hrs after 13.30.
  
  So,
  
  The required time is 19.30Hrs
• 4 years agoHelpfull: Yes(0) No(0)