Two cards are drawn at random from a pack of 52 cards.what is the probability that either both are black or both are queen?

• 2 cards drawn from 52 cards,so chances are 52C2
  chances for drawing both black cards=26C2
  chances for drawing both queen=4C2
  so we will be having 2 queens in black cards,thus it is 2C2 which is 1
  probability=(325+6-1)/1326=55/221
  
• 11 years agoHelpfull: Yes(42) No(0)
• in a pack of 52 cards, we have 26 black cards in which there are two queens included. We have two more red queens that makes a total of 4 queens. Now favourable cases are (26C2 + 4C2) and total possible no. of cases in which 2 cards can be drawn are 52C2.
  hence required probability = (26C2 + 4C2)/52C2
• 11 years agoHelpfull: Yes(9) No(13)
• meghana if u dont mind could u please stop posting ur answers
• 9 years agoHelpfull: Yes(7) No(2)
• the probability for both cards are black= 26/52*25/51
  the two black queens are considered in previous case
  therefore the another probability is only for two red queens =2/52*1/51
  the total probability= 26/52*25/51 + 2/52*1/51 =163/663
• 11 years agoHelpfull: Yes(4) No(9)
• We have n(s)=52c2=(52*51)/(2*1)=1326.
  Let A=event of getting both black cards
  B=event of getting both queens
  A&B=event of getting queen of black cards
  n(A)=26c2=(26*25)/(2*1)=325,
  n(B)=4c2=(4*3)/(2*1)=6 and
  n(A&B)=2c2=1
  P(A)=n(A)/n(S)=325/1326;
  P(B)=n(B)/n(S)=6/1326 and
  P(A&B)=n(A&B)/n(S)=1/1326
  P(AUB)=P(A)+P(B)-P(A&B)=(325+6-1/1326)=330/1326=55/221
  
  
• 10 years agoHelpfull: Yes(3) No(1)
• the answer is 331/1326
• 11 years agoHelpfull: Yes(2) No(8)
• probability for
  both cards are black => 26/52*25/51 = 25/102
  
• 11 years agoHelpfull: Yes(2) No(11)
• 30-2=18/52
• 11 years agoHelpfull: Yes(1) No(17)
• 26C2+4C2/52C2=331/1326
• 8 years agoHelpfull: Yes(1) No(1)
• ((2652)*(25/51))+((4/52)*(3/51))
  
• 9 years agoHelpfull: Yes(0) No(1)
• Ans. 26/52*25/51+ 4/52*3/51-2/52
• 8 years agoHelpfull: Yes(0) No(0)