A train which travels at a uniform speed due to some mechanical fault after traveling for an hour goes at 3/5th of the original speed and reaches the destination 2 hrs late.If the fault had occurred after traveling another 50 miles the train would have reached 40 min earlier. What is distance between the two stations.

1. 300
2. 310
3. 320
4. 305

Ans: 1.

• 3/5*x=180
  x=5*180/3
  x=900/3
  x=300
• 10 years agoHelpfull: Yes(2) No(3)
• here 1 hour + late 2 hours= 3 hours=3*60min=180
  (3/5)*x=180
  3x=180*5
  3x=900
  x=900/3=300
• 10 years agoHelpfull: Yes(2) No(3)
• x=v*1 + 3/5v(x/v-1+2)
  =>x=4v
  
  50=(40/60)*v
  =>v=75
  
  =>x=75*4=300
  
  Enjoy it....
• 10 years agoHelpfull: Yes(1) No(2)
• Distance between the two stations = 200 miles
  
  Original speed = 50 m.p.h
  Original time = 4 hours
  
• 12 years agoHelpfull: Yes(0) No(5)