A+B+C+D+E=FG, FG =10F+G

Ato G are different letters , if FG is as large as possible , what is value of G.

• FG is as large as possible and all the 7 numbers should be different.
  Let’s try out a few possibilities..
  9 + 8 + 7 + 6 + 5 = 35…5 is getting repeated twice.
  9 + 8 + 7 + 6 + 4 = 34…4 is getting repeated
  9 + 8 + 7 + 5 + 4 = 33…3 repeats
  9 + 8 + 6 + 5 + 4 = 32
  None of the numbers repeat in the above case and 32 is the maximum number FG can have. The value of G is 2.
  
• 11 years agoHelpfull: Yes(66) No(0)
• Vaibhav since A to G must have different values so F=3 and G=3 can't be possible.
• 11 years agoHelpfull: Yes(3) No(1)
• @ vaibhav,it is clearly written dat A to G must b distinct,in 33(FG),3 is repeated twice,so 32is d ans
• 11 years agoHelpfull: Yes(3) No(0)
• 9+8+7+5+2=31
• 11 years agoHelpfull: Yes(2) No(1)
• prakhar ye mene kra to mera 9+8+7+5+4=33
  ye aya par ans 32 aa rha he..
• 11 years agoHelpfull: Yes(1) No(2)
• by hit and trial fg=98 as 90+8=98 largest 2 digit number so g could be 8
• 11 years agoHelpfull: Yes(0) No(11)
• let us take the values of a,b,c,d,e=2 then fg=10
• 11 years agoHelpfull: Yes(0) No(3)