Capgemini
Company
Numerical Ability
Log and Antilog
If log2x-5logxx+6=0,then what would the value /values of x be?
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-
Log2(X) – 5 logx(X) +6 = 0
Log2(X) -5*1 +6 =0
Log2(X) = -1
X=2^(-1) =1/2
- 12 years agoHelpfull: Yes(34) No(1)
- Log2(X)-5LogX(X)+6=0
since LogX(X)=1
Log2(X)=-6+5
Log2(X)=-1
Taking Exponential
X=2^(-1)
X=1/2 - 12 years agoHelpfull: Yes(10) No(0)
- is first one is log x base 2 and second one is llog x base x?
- 12 years agoHelpfull: Yes(1) No(9)
- log(base2)x+5 log(basex)x+6=0,
log(base2)x+5*1+6=0, as log(basex)x=1,
log(base2)x+11=0,
log(base2)x=-11,
x=2^-11,
hence x=4.8828*10^-4 - 12 years agoHelpfull: Yes(0) No(8)
- logx x =1
then log2x-5+6=0
log2x=-1
log2x=log(10-1 10)
2x=1/10
x=1/20 - 12 years agoHelpfull: Yes(0) No(9)
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