If log2x-5logxx+6=0,then what would the value /values of x be?

• 
  Log2(X) – 5 logx(X) +6 = 0
  Log2(X) -5*1 +6 =0
  Log2(X) = -1
  X=2^(-1) =1/2
  
• 11 years agoHelpfull: Yes(34) No(1)
• Log2(X)-5LogX(X)+6=0
  since LogX(X)=1
  Log2(X)=-6+5
  Log2(X)=-1
  Taking Exponential
  X=2^(-1)
  X=1/2
• 11 years agoHelpfull: Yes(10) No(0)
• is first one is log x base 2 and second one is llog x base x?
• 11 years agoHelpfull: Yes(1) No(9)
• log(base2)x+5 log(basex)x+6=0,
  log(base2)x+5*1+6=0, as log(basex)x=1,
  log(base2)x+11=0,
  log(base2)x=-11,
  x=2^-11,
  hence x=4.8828*10^-4
• 11 years agoHelpfull: Yes(0) No(8)
• logx x =1
  then log2x-5+6=0
  log2x=-1
  log2x=log(10-1 10)
  2x=1/10
  x=1/20
• 11 years agoHelpfull: Yes(0) No(9)