From the third term,each term in the sequence a(1),a(2),a(3),a(4),a(5),a(6) is the sum of the preceding two terms that is a(n)=a(n-1)+a(n-2) for n=3,4,5,6.if a(5)=36 what is the sum of all the six terms?

• If x is the first term and y is second terem, then
  terms are
  x
  y
  x+y
  x+2y...... equal to 36
  2x+3y
  3x+5y
  
  sum of 6 terms = 8x+12 y = 4*(2x+3y)= 4*36=144
• 11 years agoHelpfull: Yes(19) No(1)
• =a(1)+a(2)+a(3)+a(4)+a(5)+a(6)
  =a(3)+a(3)+a(4)+{a(3)+a(4)}+{a(4)+a(5)}
  =3*{a(3)+a(4)}+a(5)
  =4*a(5)
  =4*36
  =144
• 11 years agoHelpfull: Yes(11) No(1)
• a(3)+a(4)=36=a(5)
  a(1)+a(2)+a(3)+a(4)+a(5)+a(6)=a(1)+a(2)+36+36+a(6)=36+36+36=108
• 10 years agoHelpfull: Yes(1) No(4)
• 144
  a(5)=a(3)+a(4)=36.....(1)
  now making all the terms except a(1) and a(2) in terms of a(1) and a(2) and by adding them we can find an equation which is 4 times eqn 1.
• 10 years agoHelpfull: Yes(0) No(0)