If x=(16^3+17^3+18^3+19^3),then x divided by 70 leaves a remainder of
1>0
2>1
3>69
4>35

• x=(16^3+17^3+18^3+19^3)= 21700
  21700/70 = 310
  
  
  If x=(16^3+17^3+18^3+19^3),then x divided by 70 leaves a remainder of '0' (ZERO)
  
• 12 years agoHelpfull: Yes(3) No(2)
• 16^3+19^3+17^3+18^3=(16+19)^3-3*16*19(16+19)+(17+18)^3-3*17*18(17+18)
  =(35)^3-70*(3*8*19)+(35)^3-70*(3*17*9)
  =(35+35)^3-3*35*35(70)-70*((3*8*19)+(3*17*9))
  =(70)^3-70*(3*35*35)-70*((3*8*19)+(3*17*9))
  since all factors are in multiple of 70
  answer is ZERO (0)
• 12 years agoHelpfull: Yes(3) No(2)
• x= p+q
  let p= 16^3+18^3 (Even+Even=Even) and q= 17^3++19^3(Odd+Odd=Even)
  ===>{{concept P^n+Q^n is divisible by P+Q when n is odd}}
  p is divisible by 2 and 35 it means p divided by 70.
  q is also divisible by 2 and 35 it means q divided by 70.
  So X is also decided by 70. Th remainder is 0.
• 12 years agoHelpfull: Yes(1) No(1)