Peter can cover a certain distance in 1 hr. 24 min. by covering two-third of the distance at 4 kmph and the
rest at 5 kmph. Find the total distance.

• time=distance/speed
  let total distance travelled be x in 84/60 hrs
  2/3 rd of x travelled in 4 km/hr
  1/3 rd of distance travelled in 5 km/hr
  2x/(3*4)+x/(3*5)=84/60
  x=6 km
• 12 years agoHelpfull: Yes(33) No(4)
• 2/12x + 1/15x = 7/5
  X= 6
• 12 years agoHelpfull: Yes(4) No(4)
• time=distance/speed hr = (km)/(km/hr)
  1 hr 24 min = 1.4 hr
  1.4=((2x/3)/4) + ((x/3)/5)
  x= 6 km
  
• 11 years agoHelpfull: Yes(4) No(0)
• Let total distace be x. Total time 1hr 24 min i.e (14/10)
  So 2/3of x distance by 4 kmph, 1/3 of distance bt 5 kmph.
  (((2/3x)/4)+ ((1/3x)/5)= (14/10)
  x=6 km
• 10 years agoHelpfull: Yes(3) No(0)
• hi manvir please explain clearly
• 12 years agoHelpfull: Yes(0) No(8)
• ans 6 km
  
  t=(2d/3)/4 +(d/3)/5
  where t=1 hr 24 min ie 7/5
• 11 years agoHelpfull: Yes(0) No(0)
• 6km
  total distance covered in 1hr 24 mins = 84mins
  2/3 of 84 mins= (84/3)*2=56mins
  56mins in 4kmph n rest 28mins with 5kmph=
  3.7km(in 56mins)+2.3km(in 28mins)=6km
  
• 9 years agoHelpfull: Yes(0) No(0)
• Time=Distance/Speed
  Time=1.4hr
  let distance=x
  1.4=((2x/3)/4)+((x/3)/5)
  7/5=2x/12+x/15
  x=6km
• 9 years agoHelpfull: Yes(0) No(0)
• total distance= x
  2x/3 of 4 +1x/3of 5=1hour+24/60hour
  2x/12+x/15=7/5
  after solving this equation
  x=6
• 9 years agoHelpfull: Yes(0) No(0)