Two trains are approaching each other at 60 mph each. The length of each train is 1/6 miles. When the two locomotives(engines) meet, how many seconds will it take for them to pass each other completely?

• total distance to cover= 2*(1/6)=2/6 miles
  relative speed = 60+60 = 120mph
  time taken= (2/6)/120*3600 = 10 sec.
• 14 years agoHelpfull: Yes(7) No(0)
• 10s
• 14 years agoHelpfull: Yes(1) No(0)
• total distance to cover= 2*(1/6)=2/6 miles
  relative speed = 60+60 = 120mph
  time taken= (2/6)/120*3600 = 10 sec.
• 14 years agoHelpfull: Yes(1) No(0)
• 10 minutes
• 14 years agoHelpfull: Yes(0) No(3)
• 10sec
• 14 years agoHelpfull: Yes(0) No(0)
• net speed =120.net dist to cov=1/3
  time=1/3/120/3600=10sec
• 14 years agoHelpfull: Yes(0) No(0)
• total distance to cover= 2*(1/6)=2/6 miles
  relative speed = 60+60 = 120mph
  time taken= (2/6)/120*3600 = 10 sec.
• 8 years agoHelpfull: Yes(0) No(0)