find the number of two digit positive integers n such that both n 2 and 3n are two digit positive

n will start from 20 as 20/2=10 is the lowest tow digit number and ends at 32 as 96 is the biggest tow digit number after multiplying by 3. so the series will be 20, 22, 24, 26, 28,30, 32, i.e total number of such number is 7.
10 years agoHelpfull: Yes(11) No(0)
with given conditions ,
n will be even
and
19
11 years agoHelpfull: Yes(1) No(8)
n/2 and 3n sud be integer so no. will be between 20 and 33 so
20 22 24 26 28 30 32
11 years agoHelpfull: Yes(0) No(0)
from (20-45)=26.....
11 years agoHelpfull: Yes(0) No(3)
highest 2 digit number =99
99/3=33 but(33/2)= not an integer
so take 32
while32*3=96
32/2=16
satisfies the condition
10 years agoHelpfull: Yes(0) No(0)

find the number of two digit positive integers n such that both n/2 and 3n are two digit positive integer?