j is faster than p.j and p walks a distance of 24km.The sum of speeds of j and p is 7kmph.the sum of time taken by j and p is 14hrs. then j speed is equal to . ??

• j is faster than p
  so j's speed greater than 3.5 kmph
  
  now by hit and trail method
  
  j's speed 4kmph and p's speed 3kmph
  j walks for (24/4)= 6hrs
  p walks for (24/3)= 8hrs
  their sum of time(6+8) 14hrs
  so,jspeed is 4kmph
  
  
• 11 years agoHelpfull: Yes(25) No(0)
• let j's speed=jkmph
  then p's speed=7-j kmph
  nw acc to ques. 24/j +24/7-j =14
  solving we get j=4,3
  nw j is faster so j's speeed=4kmph
• 11 years agoHelpfull: Yes(10) No(1)