A fater has 8 children ,he takes 3 at a time to a zoo.probability of a child going to the zoo.

• * the total number of children is 8.
  * 3 childen can go to the zoo at one time.
  * but the probability of a child going to zoo is=
  here one child should be going to zoo.
  so,remaining two memebers selectted from remaining 7 children.
  =1*(7C2) / 8C3.
  = 3/8
• 13 years agoHelpfull: Yes(25) No(0)
• total number of children=8
  number of possible child can go=3
  so probability of a child in zoo=3/8;
• 13 years agoHelpfull: Yes(7) No(15)
• combination of taking 3 out of 8 is 8c3=56
  now the combination of going 1 children out of 3 is 3c1=3
  
  so the probability is 3/56
• 13 years agoHelpfull: Yes(3) No(9)
• 8c1/8c3..
  acording to probability theory...
• 13 years agoHelpfull: Yes(1) No(2)
• firstly the man need to select 3 children out of 8....which is done by 8C3..
  now we only need to multiply prob. of taking one child and that is 1/8
  
  so total is...(8c3)*(1/8)
• 13 years agoHelpfull: Yes(0) No(3)
• Probabality has to be 3/8, because his father picks 3 out of 8 to go to the zoo. You have a chance of 3 out of 8 to be in that group.
• 10 years agoHelpfull: Yes(0) No(0)
• n(s)=8
  n(e)=3
  probability=n(e)/n(s)=3/8
• 8 years agoHelpfull: Yes(0) No(0)