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Probability
A fater has 8 children ,he takes 3 at a time to a zoo.probability of a child going to the zoo.
Read Solution (Total 7)
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- * the total number of children is 8.
* 3 childen can go to the zoo at one time.
* but the probability of a child going to zoo is=
here one child should be going to zoo.
so,remaining two memebers selectted from remaining 7 children.
=1*(7C2) / 8C3.
= 3/8 - 14 years agoHelpfull: Yes(25) No(0)
- total number of children=8
number of possible child can go=3
so probability of a child in zoo=3/8; - 14 years agoHelpfull: Yes(7) No(15)
- combination of taking 3 out of 8 is 8c3=56
now the combination of going 1 children out of 3 is 3c1=3
so the probability is 3/56 - 13 years agoHelpfull: Yes(3) No(9)
- 8c1/8c3..
acording to probability theory... - 13 years agoHelpfull: Yes(1) No(2)
- firstly the man need to select 3 children out of 8....which is done by 8C3..
now we only need to multiply prob. of taking one child and that is 1/8
so total is...(8c3)*(1/8) - 13 years agoHelpfull: Yes(0) No(3)
- Probabality has to be 3/8, because his father picks 3 out of 8 to go to the zoo. You have a chance of 3 out of 8 to be in that group.
- 10 years agoHelpfull: Yes(0) No(0)
- n(s)=8
n(e)=3
probability=n(e)/n(s)=3/8 - 8 years agoHelpfull: Yes(0) No(0)
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