The side of a cube is increasing @ 13 cm/sec. Determine the rate of increase in its surface area when the side is equal to 67 cm.

• let the side of cube be 's'
  rate of increase in cube side is (ds/dt)=13cm/sec
  let the total surface area of cube be 'A'
  rate of increase in cube surface area at s=67 is
  A=6*s*s
  (dA/dt)=6*2*s*(ds/dt)
  =12*67*13
  =10452 cm^2/sec
• 12 years agoHelpfull: Yes(1) No(1)