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99kg of cucumbers that were 97% water by weight somewhat got dehydrated and are now 93% water by weight.what is the new weight of the cucumbers?
Read Solution (Total 6)
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- cucumber's weight = 99kg
97% water weight => it has 99*97/100 kg of water = 96.03 kg
=> weight of content other than water = 99-96.03=2.97 kg (now lets keep this aside)
now, for calcuating wight of water when it is reduced to 93%, lets consider ratio of wight to percentage
97:96.03::93:x (where x is new weight of water)
gives x = 92.07 Kg
now adding the weight of cucumber other than water (calcuated previously) = 2.97+92.07 Kg
gives 95.04 Kg
this is the new weight of cucumber
- 11 years agoHelpfull: Yes(17) No(4)
- we have 3% of solid part that will be by weight= 99*3/100= 2.97kg
now cucumber is dehydrated so water decreased
but the solid part is same
now that is contributing as 7%
so totl weight= 2.97*100/7=42.4285kg - 11 years agoHelpfull: Yes(6) No(5)
- let x be new weight,
(100-97)*99=(100-93)=x
x=42.4 is a new weight of cucumbers - 12 years agoHelpfull: Yes(5) No(10)
- 42.42....7%of x=3%of 99....x=42.42
- 11 years agoHelpfull: Yes(1) No(2)
- new weight is (99-((99*97)/100)) + (99-((99*97)/100))*(93/100)
- 11 years agoHelpfull: Yes(0) No(0)
- let new weight is x kg
now cucumber is dehydrated ,, water decreased but the solid part is same
(100-97)% of 99 = (100-93)% of x
by solving this we get
x= 42.42 Kg - 4 years agoHelpfull: Yes(0) No(0)
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