99kg of cucumbers that were 97% water by weight somewhat got dehydrated and are now 93% water by weight.what is the new weight of the cucumbers?

• cucumber's weight = 99kg
  97% water weight => it has 99*97/100 kg of water = 96.03 kg
  => weight of content other than water = 99-96.03=2.97 kg (now lets keep this aside)
  now, for calcuating wight of water when it is reduced to 93%, lets consider ratio of wight to percentage
  97:96.03::93:x (where x is new weight of water)
  gives x = 92.07 Kg
  now adding the weight of cucumber other than water (calcuated previously) = 2.97+92.07 Kg
  gives 95.04 Kg
  
  this is the new weight of cucumber
  
• 11 years agoHelpfull: Yes(17) No(4)
• we have 3% of solid part that will be by weight= 99*3/100= 2.97kg
  now cucumber is dehydrated so water decreased
  but the solid part is same
  now that is contributing as 7%
  so totl weight= 2.97*100/7=42.4285kg
• 11 years agoHelpfull: Yes(6) No(5)
• let x be new weight,
  (100-97)*99=(100-93)=x
  x=42.4 is a new weight of cucumbers
• 11 years agoHelpfull: Yes(5) No(10)
• 42.42....7%of x=3%of 99....x=42.42
• 11 years agoHelpfull: Yes(1) No(2)
• new weight is (99-((99*97)/100)) + (99-((99*97)/100))*(93/100)
• 10 years agoHelpfull: Yes(0) No(0)
• let new weight is x kg
  now cucumber is dehydrated ,, water decreased but the solid part is same
  (100-97)% of 99 = (100-93)% of x
  by solving this we get
  x= 42.42 Kg
• 4 years agoHelpfull: Yes(0) No(0)