megha,hina and swarna went to a
party.megha bought 5 bags of
cookies and swarna bought 9bags
of cookies but hina did not bought
any bag of cookies.the cookies
were shared equally and at the end of the party hina paid rs 80 to
megha and swarna as her
share.how would megha and
swarna aplit the money.assume
that all cookie bags wre identical
and cost the same As

• megha bought 5 bags of
  cookies and swarna bought 9bags
  of cookies .
  If each bag has 3 cookies, then megha contributed 15 cookies and swarna contributed 27 cookies. so total 42 cookies.
  Each one ate 14 cookies.
  Megha gave one cookie to Hina and Swarna gave 13 cookies to Hina.
  so amt of Rs 80 will be divided betweem Megha and swarna in ratio of 1:13.
  So amt recd by megha = 80*1/14= Rs 40/7
  amt recd by Swarna = 80*13/14 = Rs 40*13/7 = Rs. 520/7
• 11 years agoHelpfull: Yes(16) No(4)
• let the no. of cookies be y in each bag. so total=14y cookies.when equally divided ,14y/3 cookies costs 80.so, y costs 120/7. so, megha paid 600/7 and swarna paid 1080/7. now, if megha gets Rs x out of hina's 80 then 600/7-x=80 that is x=40/7 means megha gets 40/7 and swarna gets 80- 40/7= 520/7.
• 11 years agoHelpfull: Yes(6) No(0)
• ratios will be 5/14 & 9/14 of Rs. 80
• 11 years agoHelpfull: Yes(2) No(0)
• megha =40/7 and swarna =80-(40/7).EXPLAINED ABOVE BY SURBHI!!!
• 11 years agoHelpfull: Yes(0) No(2)