IF X^2+2=2X
THEN THE VALUE OF
X^4-X^3+X^2+2 IS
1. 0
2. 1
3. -1
4. SQ ROOT OF 2

• 0
  
  X^2+2=2X
  X^2+1-2X = -1
  (x-1)^2 =-1
  x-1= i where i (iota) is equal to sq root of (-1).
  x=1+i
  x^2= 1-1+2i=2i
  x^4=-4
  x^3 = 2i*(1+i)
  
  putting these values in
  X^4-X^3+X^2+2
  we get
  X^4-X^3+X^2+2 =0
  
• 12 years agoHelpfull: Yes(3) No(3)
• x^4-x^3+x^2+2
  x^4-x^3+2x
  by adding +2x^2,-2x^2 and -2x,2x
  x^4+2x^2-x^3-2x+4x-2x^2
  x^2(x^2+2)-x(x^2+2)+4x-2x^2
  2x^3+4x-2x^2-2x^2
  2x(x^2+2)-4x^2
  4x^2-4x^2=0
  hence ans 1. 0
  
• 12 years agoHelpfull: Yes(1) No(2)
• answer is 0.
  X^4-X^3+X^2+2=(2X-2)^2-(2X-2)(X)+(X^2+2)
  =(2X-2)^2-(2X-2)(X)+(2X)
  WE WILL GET, =(2X^2-4X+4)
  =2*(X^2-2X+2)
  =2*(0)=0.
  SO,ANS IS 0.
• 12 years agoHelpfull: Yes(0) No(2)