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A bag contains printed articles of 4 different kinds: periodicals, novels, newspapers
and hardcovers. When 4 articles are drawn from the bag without replacement, the
following events are equally likely:
 the selection of 4 periodicals
 the selection of 1 novel and 3 periodicals
 the selection of 1 newspaper, 1 novel and 2 periodicals and
 the selection of 1 article of each kind
What is the smallest number of articles in the bag satisfying these conditions? How
many of these are of each kind?

Read Solution (Total 2)

let no. of periodicals be p, novels be nl, newspaper be np and hardcovers be h.

Then, pC1 = (nl C 1) * (p C 3) = (np C 1) * (nl C 1) * (p C 2) = (p C 1) * (nl C 1) * (np C 1) * (h C 1)

from the above equation we get,
4nl = p-3
3np = p-2
2h = p-1

Now, find the value of p (by trial and error method) which satisfies all the three equations above
We get, p=11
from above three equations, p=11, nl=2, np=3, h=5
9 years agoHelpfull: Yes(2) No(0)

periodicals=4
newspaper=1
novel=1
hardcovers=1
12 years agoHelpfull: Yes(1) No(4)

TCS Other Question

A secret message is divided into Θ parts and each part is shared with a different
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