In the sequence,
(1^2) + (2^2 + 3^2 + 4^2) + (5^2 + 6^2 + 7^2 + 8^2?+ 9^2) + . . . where each term has (2n - 1) terms,
Them which term does 40000^2 belongs to?

• 40000^2 belongs to 200th term.
  
  Sum of n terms = 1+3+5+....+(2n-1) = Sigma(2n-1) = Sigma (2n)- Sigma 1
  = 2* Sigma n -n = 2*n*(n+1)/2 -n= n^2+n-n= n^2
  here n^2=40000
  n=200
• 12 years agoHelpfull: Yes(4) No(0)