one man have some oranges. he gave half of the orange and a half peace of a orange. he also continue that to the next two. now he have zero orange. he never use kinfe. how much orange will he had at first.?

• Let x be the no of oranges
  
  After 1st time, no of oranges remaining = x - 0.5 - (x/2) = (x - 1)/2
  After second time , remaining = (x - 1)/2 - 0.5 - (x -1)/4 = (x - 3) / 4
  After 3rd time , remaining = (x - 3)/4 - 0.5 - (x - 3)/8 = (x - 7)/8
  
  Remaing oranges after 3rd time = 0
  => x = 7
  
  If he didn't use knife means no of oranges = an odd number
• 12 years agoHelpfull: Yes(2) No(0)
• Do the reverse calculation
  3rd time, no. of orange = 2*(0+1/2)=1
  2rd time, no. of orange = 2*(1+1/2)=3
  1rd time, no. of orange = 2*(2+1/2)=7
  Ans = 7 oranges
  
  
• 12 years agoHelpfull: Yes(2) No(1)