CAT
Exam
Last non-zero digit of a number 26!.
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- Last non-zero digit of a number 26!. will be 4.
Rightmost non-zero digit of n! or R(n!)
R(n!) = Last Digit of [ 2^a x R(a!) x R(b!) ]
where n = 5a + b
here n=26
a=5; b=1
R(n!) = Last Digit of [ 2^a x R(a!) x R(b!) ]
R(26!) = Last Digit of [ 2^5 x R(5!) x R(1!) ]= last digit of (2*2*1+ =4 - 11 years agoHelpfull: Yes(6) No(1)
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