Amit can complete a piece of work in 2.25 days.badri takes double the time taken by amit.chetan takes double dat of badro,and das takes double dat of chetan to complete the same task.They are split into two groups(of one or more persons)such that the differnce b/w the times taken by the two groups to complete the same work is minimum.what could be the compostion of the faster group?
a)amit and das
b)badri nd chetan
c)badri,chetan nd das
d)amit alone

• A = 2.25 days => 1 day = 1/2.25 = 0.44 work/day
  B = 4.5 days => 0.22 work / day
  C = 9 days => 0.11 work per day
  D = 18 days => 0.055 work / day
  
  
  now add all 1 day work of b,c,d then we ll get 0.345 which is less than 1 days amit work...
  so if we all add in amit's work the it will definetly increase the differnce
  so group form like, amit in a single group and another group consist of b,c,d
• 12 years agoHelpfull: Yes(48) No(1)
• Amit alone is faster group.
  other group is made of badri , chetan and Das.
  Amit can complete a piece of work in 2.25 days.
  so Amit's one day work = 4/9
  Badri's one day work = 4/18
  Chetan's one day work = 4/36
  Das's one day work = 4/72
  (B+C+D)'s one day work = 4/18+4/36+4/72= (4/9)*(1/2+1/4+1/8) = (4/9)*(7/8) i.e. 7/8 times of Amit's one day work.
• 12 years agoHelpfull: Yes(16) No(3)
• A B C D
  Days taken : 2.25 4.5 9 18
  Efficiemcy : 18 9 4.5 2.25
  
  Add Efficiency of B,C,D => 9+4.5+2.25=15.75 which is the closest to 18.
  There when efficiencies are closer Days taken are also closer. i.e minimum
  faster grp : Amit Other grp : B,C, D
• 12 years agoHelpfull: Yes(14) No(1)
• A) AMIT AND DAS
• 12 years agoHelpfull: Yes(8) No(18)
• A = 2.25 days => 1 day = 1/2.25 = 0.44 work/day
  B = 4.5 days => 0.22 work / day
  C = 9 days => 0.11 work per day
  D = 18 days => 0.055 work / day
  
  Among the options,work done per day is maximum for option a i.e. A+D
  A+D = 0.495 work/day
  => total time taken = 1/0.495 = 2 days
• 12 years agoHelpfull: Yes(5) No(11)
• calculate d difference coz the difference shd b minimum as per questn...
  (Badri+chetan+das 's 1 day work)-amit's 1 day work=7/18-4/9=1/18 which is minimum......
• 12 years agoHelpfull: Yes(4) No(1)
• amit=2.25 now 44.4% of work done in one day
  badri=5 now 20% of work done in one day
  chetan=10 now 10% of work done in one day
  das=20 now 5% of work done in one day
  so if we divide the group (20+10+5)% work in one day is less than of amit one day work
  so ans is d)
  
• 11 years agoHelpfull: Yes(4) No(0)
• Amit in 1 day can do = .44 work
  Bardi in 1 day can do = .22 work
  Das in 1 day can do = .11 work
  Chetan in 1 day can do = .05 work
  in 1 day Bardi + Das + Chetan can do = .38
  which is less than amit.
  so faster group is amit ans d).
  
• 11 years agoHelpfull: Yes(3) No(0)
• A) A + B
  As above
• 12 years agoHelpfull: Yes(2) No(13)
• the grup shud be form like a in one grrp and another group is b,c,d, such that difference b/w time taken by group to complete the work should be minimum.
  A = 2.25 days => 1 day = 1/2.25 = 0.44 work/day
  B = 4.5 days => 0.22 work / day
  C = 9 days => 0.11 work per day
  D = 18 days => 0.055 work / day
  
  
  
• 12 years agoHelpfull: Yes(2) No(3)
• answer would be d) amit alone
• 9 years agoHelpfull: Yes(1) No(0)
• answer would be badri,chetan nd das
• 11 years agoHelpfull: Yes(0) No(6)
• answer will be b
• 10 years agoHelpfull: Yes(0) No(5)
• how it is possible...?
  jab ki amit and das ek group hai...
• 9 years agoHelpfull: Yes(0) No(0)