a^3 - b^3 - 3ab = 1,
a^3 - b^3 + ab = x! + 1,
where a,b,x are positive integers,x is least.

Find (a + b) ?

• a^3 - b^3 + ab = x! + 1,
  a^3 - b^3 - 3ab = 1,
  
  subtracting,
  ab+3ab =x!
  4ab=x!
  if x=4
  a=3
  b=2
  a+b=3+2=5 and x=4.
• 11 years agoHelpfull: Yes(3) No(1)
• if a^3-b^3-3ab=1 then a=6 and b=5
  because in this type question integers are regular
  then ans of a+b is 11 and x is 5
• 11 years agoHelpfull: Yes(0) No(3)