A six-digit number is formed using all the Six digits 2, 3, 4, 5, 7,8.what is the probability that it is divisible by 11?

• If p is the Sum of the digits in the odd places and q is the Sum of the digits in the even places.
  p+q = 29
  p-q = ±11
  => (p,q)= (9,20)(20,9)
  => m= 2+3+4 and n= 5+7+8,
  the number of numbers divisible by 11 is 2(3!)^2= 72
  the total number of numbers = 6!
  probability = 72/(6!)= 1/10
  
  
• 12 years agoHelpfull: Yes(8) No(1)
• 1/120 total numbers made by 2,3,4,5,7,8 are 720 and total numbers that are divisible by 11 are 6
• 12 years agoHelpfull: Yes(0) No(3)