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Maths Puzzle
How to prove that any chord is less than that drawn through its middle point?
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- The length of chord is given by
L = 2*sqrt(r^2 - p^2) , where p is perpendicular distance of chord from centre.
When another is drawn to the chord via its centre, p2 < p1
=> L2 > L1
Thus the length of second chord is greater.
Also L1 = L2 if L1 is diameter. - 12 years agoHelpfull: Yes(0) No(1)
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